amenability and property T

#connection

• amenable groups cannot have kazhdan property T!
• the point is that amenability is really about lack of expansion:
  • for any finite set $K$, there is a set in your folner sequence which has small boundary w.r.t. $K$
• while kazhdan property T is explicitly about expansion

Proof (sketch)

• Let $Q$ any finite set in $T$ and $\eps > 0$ any choice
• The goal is to show that there's some representation $\pi$ and vector $v$ s.t. for every $g\in Q$ $|\pi(g)v-v|\leq \epsilon|v|$
• Well, by amenability, you can find a $F_n$ in your folner sequence which has an isoperimetry less than $\eps$. That is:
  $$\forall g\in Q, |gF_n\Delta F_n| \leq \eps |F_n|$$
• Now, let your $\pi$ be the overall regular representation on the group (which satisfies having no nontrivial invariant vector). And $v$ be the indicator for $F_n$. Then, amenability tells you that none of your group elements will take $v$ far! This contradicts property (T)

Themes

• groups and expansion